Math, asked by Galex8910, 9 months ago

Whole Square of:
(4a-7b)2

Answers

Answered by vermaprajvel
1

Answer:

(a- b)2 identity= a2+ b2-2ab

16a2+49b2-56ab

Answered by mridul1998
1

Answer:

Step-by-step explanation:

Remember the formula: (a-b)^2 = a^2+b^2-2*a*b

(4*a-7*b)^2 = (4*a)^2 + (7*b)^2 - 2*(4*a)*(7*b)

                = 16*a^2+49*b^2-56*a*b.

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