Question

whole square of a square minus b square + whole square of a square + b square

Answer 1

You are probably asking the formula for:
(a²-b²)²+(a²+b²)²
=>Expanding both of them we get,
(a⁴+b⁴-2a²b²) + (a⁴+b⁴+2a²b²)
Hence, on opening the brackets...
It gives, 2(a⁴+b⁴)

Answer 2

Answer:

$2(a^4+b^4)$

Step-by-step explanation:

We need to find : whole square of a square minus b square + whole square of a square + b square

Now, a square minus b square

⇒ (a² - b²)

Also, a square + b square

⇒ (a² + b²)

So, whole square of a square minus b square + whole square of a square + b square

⇒ (a² - b²)² + (a² + b²)²

$\implies a^4+b^4-2a^2b^2+a^4+b^4+2a^2b^2\\\\\implies 2a^4+2b^4\\\\ \implies 2(a^4+b^4)$