Question

whole square root of 4 a square + b square + c square + 4AB - 2 BC - 4 AC​

Answer 1

Answer:

$4a {}^{2} + b {}^{2} + c {}^{2} + 4 ac - 2bc \\ \\ of \: the \: form \: (a + b + c) {}^{2} = a {}^{2} + b {}^{2} + c {}^{2} + 2ab + 2bc + 2ac \\ \\ \\ = (2a) {}^{2} + (b) {}^{2} - (c) {}^{2} + 2(2a)(b) + 2(b)( - c) + 2(a)( - c) \\ \\ = (2a + b - c) {}^{2}$

Answer 2

Step-by-step explanation:

4a2+b2+c2+4ac−2b

(a+b+c)2=a2+b2+c2+2ab+2bc+2ac

=(2a)2+(b)2−(c)2+2(2a)(b)+2(b)(−c)+2(a)(−c)=

(2a+b−c)2