Whose area is greater? (A) Square of 12cm long side (B) Rectangle of 6cm long and 24cm
side.
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Answer:
Step-by-step explanation:
a. area of square = (side)^2
where side is given 12 cm long
therefore area of square is (12cm)^2
= 144cm^2
now b. area of rectangle = length * breadth
where l = 6 cm and b = 24 cm
therefore area of rectangle is 6 * 24 cm^2
= 144 cm ^2
by this we can conclude that both area are equal .
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Answered by
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Answer:
x^2 = A for square
x+12 = length of rectangle
x+8 = width of rectangle
2x^2 = area of rectangle
2A=(x+12)*(x+8)
2x^2= (x+12)*(x+8) plug in area of rectangle
2x^2 = x^2+20x+96 foil the right side
x^2 - 20x -96 = 0 subtract everything over to the left
x(x-24)(x+4) = 0 factor the polynomial
x = 0, 24, -4 are the possible solutions. Can’t be 0 or -4, so the length of one side of the square is 24 cm.
Thus, the area of the square is 24^2 = 576 cm^2.
x^2 = A for square
x+12 = length of rectangle
x+8 = width of rectangle
2x^2 = area of rectangle
2A=(x+12)*(x+8)
2x^2= (x+12)*(x+8) plug in area of rectangle
2x^2 = x^2+20x+96 foil the right side
x^2 - 20x -96 = 0 subtract everything over to the left
x(x-24)(x+4) = 0 factor the polynomial
x = 0, 24, -4 are the possible solutions. Can’t be 0 or -4, so the length of one side of the square is 24 cm.
Thus, the area of the square is 24^2 = 576 cm^2.
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