Math, asked by letscookituptm, 18 days ago

Whose area is greater? (A) Square of 12cm long side (B) Rectangle of 6cm long and 24cm

side. ​

Answers

Answered by ajaymilan854
0

Answer:

Step-by-step explanation:

a. area of square = (side)^2

where side is given 12 cm long

therefore area of square is (12cm)^2

= 144cm^2

now b. area of rectangle = length * breadth

where l = 6 cm and b = 24 cm

therefore area of rectangle is 6 * 24 cm^2

= 144 cm ^2

by this we can conclude that both area are equal .

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Answered by Uzumaki1610
0
Answer:

x^2 = A for square

x+12 = length of rectangle

x+8 = width of rectangle

2x^2 = area of rectangle

2A=(x+12)*(x+8)

2x^2= (x+12)*(x+8) plug in area of rectangle

2x^2 = x^2+20x+96 foil the right side

x^2 - 20x -96 = 0 subtract everything over to the left

x(x-24)(x+4) = 0 factor the polynomial

x = 0, 24, -4 are the possible solutions. Can’t be 0 or -4, so the length of one side of the square is 24 cm.

Thus, the area of the square is 24^2 = 576 cm^2.
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