Question

whose diagonal is larger _ a cuboidal of dimension 9cm×3cm×8cm or a cube of edge 11cm​ ? please help I want full explanation​ because my answer book answer is cube​

Answer 1

Answer:

The diagonal of the cube is larger.

Step-by-step explanation:

For the cuboid,

l=9 cm , b=3cm , h=8 cm

Diagonal =

$\sqrt{ {l}^{2} + {b}^{2} + {h}^{2} }$

$\sqrt{ {9}^{2} + {3}^{2} + {8}^{2} }$

=root(81+9+64)

=root(154)

=12.41(approx.)

For the cube,

s=11 cm

Diagonal=

$s \sqrt{3}$

=11×root(3)

=11×1.73

=19.03(approx.)

HENCE THE DIAGONAL OF THE CUBE IS LARGER