Question

whose length Find the perimeter of the rectangle is 40cm and length of one diagonal is 41 is 41 cm.​

Answer 1

Answer: As we know the opposite sides of a rectangle are equal.

If AB = 40 cm that means the side opposite to AB i.e. CD will also be 40 cm.

Now, one of the diagonals of a rectangle is given AC = 41 cm which divides the rectangle into two right-angled triangles.

Now, we can apply the Pythagoras theorem and find the third side that is the breadth of the rectangle.

Let the breadth of the rectangle be AD = x.

Now, in triangle ADC, by Pythagoras theorem (Hypotenuse)2 = (Perpendicular)2 + (Base)2

(AC)2 = (DC)2 + (AD)2

(41)2 = (40)2 + (x)2

1681 = 1600 +(x)2

1681 – 1600 = (x)2

x2 = 81

x = 9 cm

Therefore, breadth of the rectangle = 9 cm

As we know that Perimeter of rectangle = 2(l + b)

= 2(40 + 9)

= 2(49)

= 98 cm

Step-by-step explanation:

Answer 2

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