Question

Wht is empirical formula is C2H4O2 &n=1 ,then what will be molecular formula? ​

Answer 1

Answer:

As we know that to calculate molecular formula from the given empirical formula with the help of n is

$Mol. formula=n(empirical formula) \: \: \: \: \: \: \: \:................... (i)$

where n will be

$n = \frac{molecular \: mass}{empirical \: mass}$

(ln above formula vapour density can be given so we should multiply vapour density by 2 calculate the molecular mass of the compound)

As given that n is equals to 1 .

so using equation first molecular formula will be:-)

$Mol. formula=1(C_2H_4O_2) \\ =C_2H_4O_2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \boxed{ \boxed{ \boxed{ANSWER}}}}$