wht is tan 15°
... plz give me the ans with explanation .....
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Answered by
1
hi
i have attached ur answer
hope it helps...❤
i have attached ur answer
hope it helps...❤
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aarushi94:
thanks
Answered by
1
we know that,
tan(A - B)= tanA-tanB/1+tanAtanB
tan15° = tan(45°-30°)
=tan45°-tan30°/1+tan45°tan30°
=(1-1/√3)/(1+1*1/√3)
=(√3-1)/(√3+1)
tan(A - B)= tanA-tanB/1+tanAtanB
tan15° = tan(45°-30°)
=tan45°-tan30°/1+tan45°tan30°
=(1-1/√3)/(1+1*1/√3)
=(√3-1)/(√3+1)
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