Question

Wht's is the missing number 7,13,25,49​

Answer 1

Answer:

Answer would be 97.

Step-by-step explanation:

Answer 2

Answer:

from the sequence we can see that it follows the recurrence relation

Tn=2Tn−1,n>0,T0=4

now, Tn

=2Tn−1−1

=2(2Tn−2−1)−1

=22Tn−2−2−1

=22(2Tn−3−1)−2−1

=23Tn−3−(1+2+22)

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.

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=2n(T0)−(20+21+22+…+2n−1)

(20+21+22+…+2n−1)=2n−1,

using the formula, a(1−rn)/(1−r),

where a is the first term of the sequence(a = 1 here), r is the common ratio ( r = 2 here) , and n is the number of total terms

=2n(T0)−(2n−1)

=2n(T0–1)+1

=3∗2n+1, where T0=4 is considered

so we have derived a closed form of the given sequence, now we can determine any term in it without knowing the previous one.

you require, T7=3∗27+1=385