Question

why 1/4and-1 are the Zeroes
of p (n) = 4x² + 3x - 1​

Answer 1

Answer:

4x^2 + 4x-x - 1

4x(x+1 ) -1 ( x+1 )

(4x-1)(x+1)

now zeros for 4x-1=0

4x=1

x = 1/4

x+1=0

x= -1

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Answer 2

Step-by-step explanation:

4x² + 3x - 1

by middle term splitting method,

sum = 3 = 4 + (-1)

product = -4 = 4 × -1

=> 4x² + 4x -x -1

= 4x ( x+1) -1 ( x+1)

= (4x-1) (x+1) = 0

=> 4x-1 = 0

=> x = 1/4

=> x+1 = 0

=> x = -1

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