Why 100 is used as modulo in finding last two digits of 49^19 using chinese remainder theorem?
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Answer:
There is only one number that satisfies the congruences by the Chinese Remainder Theorem.The number is modulo 100
Step-by-step explanation:
The Chinese remainder theorem provides with a unique solution to simultaneous linear congruences with the coprime modulo. The modulo generally being 100.
49^19 (Given)
By using Chinese remainder theorem,
x ≡ 49^19 mod 100
100 = 25 * 4
x ≡ 49^19 mod 25
x ≡ 49^19 mod 4
( 49 )^19 = ( -1 )^19 mod 25
-1 mod 25
( 49 )^19 = ( 1 )^19 mod 4
1 mod 4
x ≡ ( ( -1 ) ( 4 ) ( 19 ) ) + ( ( 1 ) ( 25 ) ( 1 ) )
x ≡ -51 mod 100
x ≡ 49 mod 100
Hence, the last two digits of 49^19 is 49.
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