Question

Why √3,√6,√9,√12 is not an Ap??​

Answer 1

Answer:

The difference between consecutive terms is not constant.

$\sqrt{6} - \sqrt{3} = \sqrt{3} ( \sqrt{2} - 1) \\ \sqrt{9} - \sqrt{6} = \sqrt{3} ( \sqrt{3} - \sqrt{2} ) \\ \sqrt{12} - \sqrt{9} = \sqrt{3} ( 2 - \sqrt{3} )$

None of the differences is same.

Step-by-step explanation:

In A.P. , the difference between consecutive terms is constant.