Question

Why a small bubble rises slowly through a liquid whereas the bigger
bubble rises rapidly?

Answer 1

the bigger bubble produces more buoyant force than small bubble so the bigger bubble goes up rapidly
 

Answer 2

Answer:

As $v \propto \mathrm{r}^{2}$, As a result, smaller air bubbles rise slower through a liquid than larger ones.

Explanation:

A bubble is related to its volume .

Because a larger bubble has more volume, it will rise faster than a smaller one.

We know that the terminal velocity is calculated as follows:

$v=\frac{2 r^{2}(\rho-\sigma) g}{9 \eta}$

The density of air is $\rho$,

while the density of the liquid is $\sigma$

It is clear that the factor $(\rho-\sigma)$, and hence, $v$ will be negative.

Now, since $v \propto \mathrm{r}^{2}$,

As a result, smaller air bubbles rise slower through a liquid than larger ones.