Why {any number }/ 0 = infinity
example: 23/0 = infinity how ?
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Answered by
0
HEY!!
We cannot find any answer for division by zero.
Look at the following observation.
If you divide 8 by 4, the answer is 2 because 4 × 2 = 8.
When you divide 8 by 0, then what number multiplied with 0 gives 8.
The answer is, no number; as we know that 0 × any number = 0 (not 8).
So, we say that division by 0 is undefined.
Infinity ‘∞’ is the notation for undefined.
So, we can say that any number divided by 0 is infinity.
We cannot find any answer for division by zero.
Look at the following observation.
If you divide 8 by 4, the answer is 2 because 4 × 2 = 8.
When you divide 8 by 0, then what number multiplied with 0 gives 8.
The answer is, no number; as we know that 0 × any number = 0 (not 8).
So, we say that division by 0 is undefined.
Infinity ‘∞’ is the notation for undefined.
So, we can say that any number divided by 0 is infinity.
Answered by
0
Not it ain't.
There are many approach to this, and all of em lead to a different solution. For clarification, I'ma mention beforehand that any number divided into parts of zero is simply UNDEFINED. Now, I can't (it's literally time consuming) take the effort to prove by every method, so I'll present my solution using limits:
So, let's start of with a function
f(x) = n/x
Where n is any real number.
So, the right hand limit for f(x) as x approaches zero is a very very very very big POSITIVE number, I mean imagine dividing and ordinary number with a number having almost infinite number of zeros after decimal, before a final significant figure!
Now, let's take the left hand limit of the same, it surely will be a very very very very big number, but WITH NEGATIVE SIGN, aka it'll blow up to NEGATIVE INFINITY !
Now since we are concerned about the point at which function takes the x as zero, aka f(0) - the value of which on the graph Does not Exist, since there is NO OVERALL Limit for f(x), a.k.a. the function isn't continuous!
So, as I have stated before, any number divided by zero is UNDEFINED, not at all infinity!
There are many approach to this, and all of em lead to a different solution. For clarification, I'ma mention beforehand that any number divided into parts of zero is simply UNDEFINED. Now, I can't (it's literally time consuming) take the effort to prove by every method, so I'll present my solution using limits:
So, let's start of with a function
f(x) = n/x
Where n is any real number.
So, the right hand limit for f(x) as x approaches zero is a very very very very big POSITIVE number, I mean imagine dividing and ordinary number with a number having almost infinite number of zeros after decimal, before a final significant figure!
Now, let's take the left hand limit of the same, it surely will be a very very very very big number, but WITH NEGATIVE SIGN, aka it'll blow up to NEGATIVE INFINITY !
Now since we are concerned about the point at which function takes the x as zero, aka f(0) - the value of which on the graph Does not Exist, since there is NO OVERALL Limit for f(x), a.k.a. the function isn't continuous!
So, as I have stated before, any number divided by zero is UNDEFINED, not at all infinity!
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