Question

Why are
and - 1 zeroes of the polynomials p(x) = 4x2 + 3x - 1?​

Answer 1

Answer:

Hey dear !!!

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==> In the given equation ,

p(x) = 4x² + 3x + 7

And α = alpha , β = beta are the zeroes of the given polynomial .

We have to find the value of ,

1/α + 1/β

So, lets find this,

We have the following values ,as

a = 4

b = 3

c = 7

We know that,

α + β = -b/a

= -3/4

Also we know that,

αβ = c/a

= 7/4

Now, by using the identity of quadratic expression ,[ 1/α + 1/β = α+β/αβ ]

By putting the obtained value we get,

1/α + 1/β = α+β/αβ

= -3/4/74

4 and 4 get cancelled and we get

= -3/7

Therefore 1/α + 1/β = -3/7

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Answer 2

$\huge\fbox {\color {red}{Answer}}$

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zero means that no. which satisfy the equation (which make the answer of given equation "0")

now see that -1 is a zero of the equation.

$4 {x}^{2} + 3x - 1$

$4 \times {( - 1)}^{2} + 3( - 1) - 1$

$4 - 3 - 1 = 4 - 4$

$= 0$

•°• -1 is a zero of this equation.

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