Why are spin 1/2 baryons less massive/energetic than spin 3/2 ones?
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I am just wondering why the lower spin state multiplets for both baryons (when looking at L=0L=0 and considering only the u d and s quarks) are lower in energy i.e. the 1/2+ multiplet is lower than the 3/2+ multiplet. This might well be obvious but I can't seem to come up with an argument for why it is the higher spin state that is the excited state. It is the same situation with mesons and the 0- and 1- multiplets.
When I look for an analogy with the two electron helium atom in atomic physics the differences in energy of different spin states arrises due to differences in symmetry in the spatial part of the wave function which in turn alters the electromagnetic potential and hence alters the energy but I can't really see a similar argument here.
When I look for an analogy with the two electron helium atom in atomic physics the differences in energy of different spin states arrises due to differences in symmetry in the spatial part of the wave function which in turn alters the electromagnetic potential and hence alters the energy but I can't really see a similar argument here.
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I then presume that in cases where the quarks are all distinguishable (such as mesons or uds baryons) the spin part changing forces a change in the flavour part which in turn leads to a different strong potential and mass difference. I'm not completely convinced but it feels like it's getting there
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