Chemistry, asked by arjunranjanmylo, 6 months ago

why aren't there 5 resonating structures of ch2-c6h5 where ch2 is a free radical.

by the 5th structure I am talking about the structure in which all pi bonds go in mirror position while radical is still on ch2.

Attachments:

Answers

Answered by ganeshholge7
0

Answer:

... by the 5th structure I am talking about the structure in which all pi bonds go in mirror position while radical is still on ch2 .

Similar questions