Physics, asked by asksandeepraj1290, 11 months ago

Why collector voltage is higher than emitter voltage?

Answers

Answered by Anonymous

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The breakdown voltage depends on the width of the depletion layer and the doping levels. Because of the heavy doping level, the emitter diode has a low breakdown voltage approximately 5 to 30 V. The collector diode is less heavily doped so its breakdown voltage is higher around 20 to 300 V.

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Answered by singlesitaarat31

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I'm reading a tutorial on basic transistor operation. It says for an npn transistor to operate such conditions are necessary:

VC > VE, by at least a few X 0.1V

VB > VE

VC > VB

We do not exceed maximum ratings for voltage differences or currents

Here I don't get why VC > VB is necessary. It looks to be if VC is bigger than VB, then the current will flow thorough the base.

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