Why coordination compounds do not lose their identity in aqueous solution?
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Coordination compounds have a formal covalent bond between the transition metal (Cu) and the ligand (NH3). For example, when an aqueous solution of copper (II) chloride is reacted with ammonia, you obtain Cu(NH3)42+ ions, and 2 Cl- ions. There is a formal bond between Cu and Nitrogen of ammonia that does not break or ionize when dissolved in water.
A coordination compound is no different than a real chemical compound, and it does not revert to the component chemicals (CuCl2 and NH3 in the above example) just because you re-suspend it in water.
A double salt exists only in solid state. It is prepared by co-crystalization of two different salts that have similar crystal structures. For example, you can crystallize a double salt of MgCa(CO3)2 from an aqueous solution containing CaCO3 and MgCO3.
Once a double salt is re-suspendedin water, it reverts to the original form of MgCO3 and CaCO3. Double salts behave like a mixture of the two individual salts.
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Coordination compounds have a formal covalent bond between the transition metal (Cu) and the ligand (NH3). For example, when an aqueous solution of copper (II) chloride is reacted with ammonia, you obtain Cu(NH3)42+ ions, and 2 Cl- ions. There is a formal bond between Cu and Nitrogen of ammonia that does not break or ionize when dissolved in water.
A coordination compound is no different than a real chemical compound, and it does not revert to the component chemicals (CuCl2 and NH3 in the above example) just because you re-suspend it in water.
A double salt exists only in solid state. It is prepared by co-crystalization of two different salts that have similar crystal structures. For example, you can crystallize a double salt of MgCa(CO3)2 from an aqueous solution containing CaCO3 and MgCO3.
Once a double salt is re-suspendedin water, it reverts to the original form of MgCO3 and CaCO3. Double salts behave like a mixture of the two individual salts.
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