Question

why CuI2(copper iodide)does not exiast?

Answer 1

Iodide ions are strong reducing agents. Therefore, Copper (II) Iodide reduces to insoluble copper (I) iodide. Thus making CuI2, CuI. CuI is not stable, so it doesn't exist in solution. It isn't stable because of electrochem and the solubility. 

I hope that this helps a bit

Answer 2

Answer:

The  reason is since I(-1) is a powerful reducing agent, it reduces Cu(II) to Cu(I) spontaneously. Hence, the existence of CuI2 is not possible.

Explanation:

• $Cu^{2+}$ is more stable than $Cu^{+}$ because of high hydration enthalpy. In case of iodine I ,$Cu^{+2}$   oxidizes $I^{-}$ to $I^{2}$ .Hence, CuI2(copper iodide) is not known and does not exist.

• Iodide ion acts as reducing agent that converts Cu(II) to Cu(I) and part of iodide ion which further oxidized to iodine. The  reaction involved is  :2Cu2+(aq)+4I−(aq)→2CuI(s)+I2(aq)