why did the artists and crafsmen of Harappan period preferred to use animals, birds and plants?
Answers
Explanation:
\large\underline\red{GIVEN,}GIVEN,
\sf\dashrightarrow \blue{THE\:GIVEN\:FRACTION\:IS\:A\:RATIONAL\:NUMBER.}⇢THEGIVENFRACTIONISARATIONALNUMBER.
\sf\dashrightarrow {\blue{\mathbb{\text{ denominator is less than its numerator by 5.}}}}⇢ denominator is less than its numerator by 5.
\sf\therefore \blue{let\:the\:numerator\:be\:x}∴letthenumeratorbex
\sf\dashrightarrow \blue{denominator= x-5}⇢denominator=x−5
\sf\dashrightarrow \blue{\dfrac{x}{x-5}}⇢x−5x
\sf\dashrightarrow \bold\pink{if \:5 \:is \:added\: to \:the \:numerator, \:numerator \:becomes\: ; \dfrac{11}{6}}⇢if5isaddedtothenumerator,numeratorbecomes;611
\sf\dashrightarrow \red{numerator= x+5}⇢numerator=x+5
THE EQUATION FORM IS,
\rm{\boxed{\sf{\green{ \circ\:\: \dfrac{x+5}{x-5} = \dfrac{11}{6}\:\: \circ}}}}∘x−5x+5=611∘
\large\underline\purple{TO\:FIND,}TOFIND,
\sf\dashrightarrow \red{\:THE\:ORIGINAL\:RATIONAL\:NUMBER}⇢THEORIGINALRATIONALNUMBER
\sf\implies \green{\dfrac{x + 5}{x - 5} = \dfrac{11}{6}}⟹x−5x+5=611
\sf\implies \green{6 \times (x+5)= 11 \times (x-5)}⟹6×(x+5)=11×(x−5)
\sf\implies \green{6x+30= 11x-55}⟹6x+30=11x−55
\sf\implies \green{30+55=11x-6x}⟹30+55=11x−6x
\sf\implies \green{85= 5x}⟹85=5x
\sf\implies \green{x= \dfrac{85}{5}}⟹x=585
\sf\implies \green{x= \cancel \dfrac{85}{5}}⟹x=585
\sf\implies \orange{x = 17}⟹x=17
\rm{\boxed{\sf{ \circ\:\: x= 17 \:\: \circ}}}∘x=17∘
THE ORIGINAL NUMBERS ARE,
\sf\implies \red{numerator=x =17}⟹numerator=x=17
\sf\implies \red{d enominator= x-5}⟹denominator=x−5
\sf\implies \red{denominator=17-5}⟹denominator=17−5
\sf\implies \pink{denominator=12}⟹denominator=12
\large\underline\orange{FRACTION,}FRACTION,
\sf\dashrightarrow \purple{\dfrac{x}{x-5}= \dfrac{17}{12}}⇢x−5x=1217
\sf\dashrightarrow \purple{\dfrac{NUMERATOR}{DENOMINATOR}= \dfrac{17}{12}}⇢DENOMINATORNUMERATOR=1217
\rm\underline\blue{NUMERATOR\:IS\:17\:AND\: DENOMINATOR\:IS\:12}NUMERATORIS17ANDDENOMINATORIS12
\rm{\boxed{\sf{ \circ\:\: \dfrac{NUMERATOR}{DENOMINATOR}= \dfrac{17}{12} \:\: \circ}}}∘DENOMINATORNUMERATOR=1217∘
Explanation:
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