Question

Why do the chelating ligands haing a system of alternate
single and double bonds from highly stable complexes?
Explain with example ?​

Answer 1

hope it helps you best of luck

Answer 2

Answer:

Chelating ligands are ligands that can join with the central atom to produce a ring-like structure. Chelating ligands include all polydentate ligands.

Explanation:

Monodendate ligands do not generate as stable complexes as chelate ligands do. This is mostly due to the fact that the "chelate effect is entropy-driven." This is how it may be explained:

Let's look at two equilibriums:

[Co(H₂O)₆]²⁺+ 6NH₃ → [Co(NH3)6]³⁺ + 6H₂O

[Co(H₂O)₆]²⁺ + 3en → [Co(en)3]²⁺ + 6H₂O

S = 0 in the first example (same number of molecules on either side).

S = +ve in the second example (4 molecules result in (6+1) = 7 molecules).

NH₃ and en have the same electronic structure.

Through the atom N, both bond.

Lewis has comparable basic strengths.

Each time, six Co-N bonds were created.

As a result, the H values of the two reactions are almost identical. However, if we compare the values of their equilibrium constants, the second equilibrium has a K value that is around 105 times greater than the first one.

The chelate effect is hence entropy-driven. The number of binding groups a ligand has affects how positive S is and how much Kf will increase as a result.

Hence, the chelating ligands have a system of alternate

single and double bonds form highly stable complexes.

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