Question

Why do we consider dU= d(qv) in adiabatic process?

Answer 1

Hii friend,

Here is your answer...

According to first law of thermodynamics ,

dU =dq + dw ......(1)

Since there is no heat evolved in adiabatic process,

dU =dw....... (2) (dq =0)

We know that, (in electrostatics concept)

Work done = potential difference × charge
(W =Vq).........(3)

Then apply (3) in (2).

dU = d (Vq)....

This it is proved.

Hope this helps you a little!!!

Answer 2

Heya...

===== Answer ======

By using the first law of thermodynamics :-

dU = dq + dw .... (1)

No heat evolved in this :-

du = dw .... (2) where dq = 0

We know that
Work done = potential difference X charge

W = Vq ... (3)

By putting 3 in 2

du = ( Vq )

It is proved ...

Thank you