why do we take theta as 180 to solve the equation in this question.plz explain
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Let the two vector be A and B .
Since , maximum and minimum magnitude of the resultant of two vectors are 17 and 7 respectively .
we kown that for maximum magnitude angle between two vectors is 0°
So, √A^2+B^2+2ABcos@ = 17
=> √A^2+B^2+2ABcos0° = 17
=> √A^2+B^2+2AB = 17 [ °•° cos0° = 1 ]
=> A+B = 17 .........(1)
we also knoe that for minimum magnitude angle between two vector is 180°.
So, √A^2+B^2+2ABcos180° = 7
=> √A^2+B^2-2AB = 7 [ °•° cos180° = -1 ]
=> A - B = 7 .......(2)
adding equation (1) & (2) , we get
2A = 24
=> A = 24/2
=> A = 12
put this value in equation (1) , we get
12 + B = 17
=> B = 5
Such that , vector A = 12 and B = 5
Since , angle between both vector is 90°.
Therefore ,
|A+B| = √A^2+B^2+2ABcos90°
= √12^2+5^2 [ °•° cos90° = 0 ]
= √169 = 13
Hence , magnitude of their resultant is 13
option (d) is right
we take 180° because magnitude of two vectors is minimum only when angle between them is 180°
【 Hope it helps you 】
Let the two vector be A and B .
Since , maximum and minimum magnitude of the resultant of two vectors are 17 and 7 respectively .
we kown that for maximum magnitude angle between two vectors is 0°
So, √A^2+B^2+2ABcos@ = 17
=> √A^2+B^2+2ABcos0° = 17
=> √A^2+B^2+2AB = 17 [ °•° cos0° = 1 ]
=> A+B = 17 .........(1)
we also knoe that for minimum magnitude angle between two vector is 180°.
So, √A^2+B^2+2ABcos180° = 7
=> √A^2+B^2-2AB = 7 [ °•° cos180° = -1 ]
=> A - B = 7 .......(2)
adding equation (1) & (2) , we get
2A = 24
=> A = 24/2
=> A = 12
put this value in equation (1) , we get
12 + B = 17
=> B = 5
Such that , vector A = 12 and B = 5
Since , angle between both vector is 90°.
Therefore ,
|A+B| = √A^2+B^2+2ABcos90°
= √12^2+5^2 [ °•° cos90° = 0 ]
= √169 = 13
Hence , magnitude of their resultant is 13
option (d) is right
we take 180° because magnitude of two vectors is minimum only when angle between them is 180°
【 Hope it helps you 】
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