Why does 1 mol of sodium chloride depress the freezing point of 1 kg of water almost twice as much as 1 mol of glycerin?
Answers
Explanation:
yes. depression in freezing point point is a colligative property which depend on number of particles.
since sodium chloride gives 2 parties per molecule in solution whereas glycerin is not ionic compound and doesn't dissociate in solution and one particle per molecule is delivered in solution.
The depression of the freezing point of a solvent depends on the number of solute particles in the solution. Sodium chloride dissociates into two ions (Na+ and Cl-) in water, so 1 mole of NaCl in water will produce 2 moles of solute particles. On the other hand, glycerin does not dissociate in water and remains as a single molecule, so 1 mole of glycerin in water produces only 1 mole of solute particles.
Since the degree of depression of the freezing point is directly proportional to the number of solute particles in the solution, 1 mole of NaCl produces a greater depression of the freezing point of water than 1 mole of glycerin. Therefore, 1 mol of sodium chloride depresses the freezing point of 1 kg of water almost twice as much as 1 mol of glycerin.
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