Physics, asked by M3khadeejasyed, 6 months ago

why does 45° gives maximum launch range?​

Answers

Answered by kirtaniaskk
1

The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range punts 2θ = 90 degrees and, therefore, θ = 45 degrees. A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.

Hope it was helpful,

Please mark my answer as the brainliest answer.

Answered by Anonymous
1

\huge\color{red}{ \boxed{ \boxed{☆Answer☆}}}

As ball speed increases, so does the drag force and the lower is the required launch angle. A launch at 45 degrees would allow the ball to remain in the air for a longer time, but it would then be launched at a lower horizontal speed at the start and it would slow down more because of the longer flight time.

  • The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range punts 2θ = 90 degrees and, therefore, θ = 45 degrees. A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.
Similar questions