Why does a capacitor loses its charge every second
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The problem of the "energy stored on a capacitor" is a classic one because it has some counterintuitive elements. ... But half of that energy is dissipated in heat in the resistance of the charging pathway, and only QVb/2 is finally stored on the capacitor at equilibrium
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Let the charge on the capacitor be “q” initially.’
After 1 sec, it is q/2
After 2 sec, it is q/4
After 3 sec, it is q/8
After 4 sec, it is q/16
After 5 sec, it is q/32
Given that q/32 = Q
Therefore q = 32Q
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