Question

why does a tungston wire of length 20cm as stretched by 0.1cm. find the strain on the curve?​

Answer 1

Answer:

Hey mate here is your answer ✌✌

Wires length (l)=20 cm = 0.2 cm

elongation(e)=0.1 cm=1/1000

strain = e/l

strain= 1/0.2 × 1000

5/1000

0.005

Hope u like this ✌✌

Answer 2

HLO MATE HERE U GO

FORMULA : Strain = e /L

Given that

L = 20 cm

e= 0.1cm

Therefore

strain = e/L

==> 0.1/20

==> 0.005 .