why does boron form stable electron deficient compounds?
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Due to its small size and high charge density, boron prefers to form covalent compounds rather than ionic compounds.
It has 3 valence electrons which it prefers to share rather than donate as B3+ ions is very small and unstable, hence it forms a sextet rather than octet.
It has 3 valence electrons which it prefers to share rather than donate as B3+ ions is very small and unstable, hence it forms a sextet rather than octet.
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