Question

Why does friction between two surfaces increase when they are proceed harder ? give an activity to show the above effect​

Answer 1

Answer:

$\huge\underline\mathfrak\blue{answer}$

Friction between two surfaces increases when they are pressed harder because there are irregularities between two surfaces which tries to lock the two surfaces. When two surfaces are rubbed harder then irregularities get more time to increase their contact which in turn lead to increased friction.

Answer 2

Answer:

$\mathcal\pink{HELLO}$

byusinghypotenusewecanfindPR

⟹(PQ)

2

+(QR)

2

=(PR)

2

⟹8

2

+15

2

=(PR)

2

⟹PR=17

⟹SismidpointofPR

\begin{gathered}\implies \sf \blue{T\:is \:midpoint\:of\:PQ}\\ \implies \sf \blue{PT\: is\:4cm}\\ \implies \sf \blue{(PT)^2+(TS)^2=(PS)^2}\\ \implies \sf \blue {4^2+(TS)^2=(8.5)^2}\\ \implies \sf \blue {(TS)^2=72.25-16}\\ \implies \sf \blue {TS=7.5}\\ \implies \sf \blue {\triangle TSQ\: is\: a\:right \:angle\:so}\\ \implies \sf \blue {(7.5)^2+4^2=(QS)^2}\\ \implies \sf \blue {QS=72.25\:is\:your\:answer}\end{gathered}

⟹TismidpointofPQ

⟹PTis4cm

⟹(PT)

2

+(TS)

2

=(PS)

2

⟹4

2

+(TS)

2

=(8.5)

2

⟹(TS)

2

=72.25−16

⟹TS=7.5

⟹△TSQisarightangleso

⟹(7.5)

2

+4

2

=(QS)

2

⟹QS=72.25isyouranswer