Physics, asked by Jeevankanth8641, 1 year ago

Why does renormalizability mean that “ultimately locality will have to be abandoned”?

Answers

Answered by vrrunda
0
This is stated by Zinn-Justin in his paper Quantum Field Theory: renormalization and the renormalization group:

Low energy physics does not depend on all the details of the microscopic model because some RG has an IR fixed point or at least a low dimension fixed surface. Of course at this stage the next more fundamental theory may still assume the form of a local quantum field theory, but ultimately locality will have to be abandoned.

Where does the connection between the fact that low energy physics does not depend on all details of the microscopic model and that "ultimately locality will have to be abandoned" come from?

Answered by Anonymous
0
Low energy physics does not depend on all the details of the microscopic model because some RG has an IR fixed point or at least a low dimension fixed surface. Of course at this stage the next more fundamental theory may still assume the form of a local quantum field theory, but ultimately locality will have to be abandoned.

Where does the connection between the fact that low energy physics does not depend on all details of the microscopic model and that "ultimately locality will have to be abandoned" come from
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