Why does sulphur in vapour state exhibits paramagnetism?
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In vapour state, Sulphur partly exists as S2molecule, which has two unpaired electrons in antibinding pie orbitals, just like the O2molecule. Hence, it exhibits paramagnetism. Because in vapour state it exists as S2 molecule and has 2 unpaired electrons in antibonding pi orbital and hence exhibit paramagnetism
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Sulphur in vapour state exhibits paramagnetism. In vapour state, sulphurpartly exists as S2 molecule and has two unpaired electrons like O2 in the antibonding π-orbital. Hence, exhibits paramagnetism.
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