Question

Why does the gun recoil when a bullet is fired from it?

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Answer 1

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Why does the gun recoil when a bullet is fired from it?

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When a gun is fired, the force of the gas produced by burning gunpowder hurls out of the bullet.

Hence, in accordance with the Newton's third law of motion, the gun itself recoils backwards, i.e., in the opposite direction of the bullet.

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Answer 2

Question

Why does the gun recoil when a bullet is fired from it?

Answer

Before firing the gun, both the gun and bullet are at rest, so the total momentum of the system is zero. As the gun is fired, bullet shoots out of the gun and acquires momentum, To conserve momentum of the system, the gun recoil. According to the law of conservation of momentum, the total momentum of the gun and the bullet will also be zero after the gun is fired. Let m be the mass of the bullet and v be its velocity on firing the gun; M be the mass of the gun and V be the velocity with which it recoils. Thus The total momentum of the gun and bullet after firing the gun will be;

The total momentum

of the gun and bullet. = MV + mv

after firing the gun

According to law of conservation of momentum.

$\begin{array}{| c | c |c| }</p><p>{ \sf{The \: total \: momentum \: of \: the}}& &{\sf{The \: total \: momentum \: of \: the}}\\</p><p> {\sf{ gun \: and \: bullet \: </p><p>after} }&=&{\sf{ gun \: and \: bullet \: </p><p>before}}\\ {\sf{ firing \: the \: gun}}& &{\sf{ firing \: the \: gun}}</p><p>\end{array}$

• M V + m v = 0
• M V = m v

$\sf {V = - \frac{m}{M} v } \: \: \: \: \: \: \: \: \: e.q2$

E.q gives the Velocity V of the gun.Negative sign indicates that velocity of the gun is opposite to the velocity of the bullet. i.e., the gun opposite to recoils. Since mass of the gun is much larger than the bullet, therefore, the recoil is much smaller than the gun velocity of the bullet.

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