why does the polynomial graph start with plus sign always in class 11...???
Answers
Answer:
Well it's not anything mandatory that the polynomial's sign in graph using wavy curve method that the first sign put up should be positive while dealing with inequalities. It's there for a reason.
For example, you have the polynomial inequality
(x-a)(x-b)>0
Then it's critical points here clearly are a and b and also suppose that a>b
So, now while assigning the positive sign to the right side of the polynomial it is because any number greater than a substituted for in place of x will give you a positive value as a whole since that value will be both greater than a as well as b
And hence for consistency of the inequality the sign assigned is positive.
I hope now your doubt would be cleared ,
similar thing goes on, in between a and b since any value of x substituted for in place of x is gonna give you a negative value as that value will be greater than b but less than a and hence a negative value of the product as a whole, and hence there we assign the negative value.
I hope this helps you ! 。◕‿◕。
Answer:
Well it's not anything mandatory that the polynomial's sign in graph using wavy curve method that the first sign put up should be positive while dealing with inequalities. It's there for a reason.
For example, you have the polynomial inequality
(x-a)(x-b)>0
Then it's critical points here clearly are a and b and also suppose that a>b
So, now while assigning the positive sign to the right side of the polynomial it is because any number greater than a substituted for in place of x will give you a positive value as a whole since that value will be both greater than a as well as b
And hence for consistency of the inequality the sign assigned is positive.
I hope now your doubt would be cleared ,
similar thing goes on, in between a and b since any value of x substituted for in place of x is gonna give you a negative value as that value will be greater than b but less than a and hence a negative value of the product as a whole, and hence there we assign the negative value.