Why does the Unruh effect not cause a physical contradiction?
Answers
Answered by
0
If the surrounding space is at an elevated temperature, would not the observer see this heat transferring to the object in question and thus melting it? If not, how in hir accelerated frame does sie account for the fact that the heat of the space is not transferring to the object? I suppose this could be considered even more simply than thinking about melting - why does sie not observe the object to increase in temperature, absorbing heat
Answered by
0
If the Unruh effect says that the temperature of space depends on one's acceleration, such that an accelerating observer will observe that hir vacuum consists of a thermal bath at some elevated temperature, then how come this does not lead to hir observing objectively different temperature-related phenomena in hir frame than an observer at rest? What I mean by that is this: suppose that in the space there is an ice cube, and the observers are sitting next to or passing by it. The observer at rest will see the cube as frozen. But suppose the accelerating observer is accelerating so hard that to hir, sie sees the space as having a temperature above the freezing point of water. Why then will sie not observe the ice cube to be melting? (Two observers cannot disagree on whether or not an object is melted, after all. Also, if you think something like "sie is moving too fast to perceive it" then just make the 'ice cube' really REALLY small, like a tiny cluster of molecules kind of small, and also at a suitably large distance.)
Similar questions