Why doesn't voltage drop naturally as a charge moves through the circuit?
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Because we are using the approximation of an ideal conductor. Within an ideal conductor, the electric field is zero; particles rearrange in a perfect manner to cancel out the electric field.
When there is no field, there is no change in the kinetic energy of particles - thus, there is no change in the potential energy either.
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When there is no field, there is no change in the kinetic energy of particles - thus, there is no change in the potential energy either.
HOPE IT HELPS
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