Why don't low frequency phonons scatter electrons in a superconductor?
Answers
Answered by
0
HEYA!!
The answer is :-
A crystal at any finite temperature has phonons, as longer wavelength phonons require less energy to be excited. It seems that the electron (or cooper pair composite particle) wave would be scattered by phonon-induced inhomogeneities in the potential, much like a bumpy road where the bumps are continuously changing. Scattering would create resistance, but in superconductors (below the critical temperature) there is none. Why is said scattering completely suppressed at finite temperature
^_^
Answered by
0
In a superconductor electron pair occupancy is defined by the probability that "Low frequency" EM crosstalk, as explain here by E. Yu.
Similar questions