why EF is taken as the height of ∆BDE if it is already the height of ∆FEB?
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I will not ask you to specify the exact EF.
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It is the height of both the triangles, BDE as well as FEB.
Since BDE is an obtuse-angled triangle, it’s perpendicular/height is outside the triangle.
In order to prove the theorem, this step is reqd.
Hope this helps u :)
Since BDE is an obtuse-angled triangle, it’s perpendicular/height is outside the triangle.
In order to prove the theorem, this step is reqd.
Hope this helps u :)
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