why electric field lines of a conductor is perpendicular to its surface though we know that the field lines emerging from a charged object spreads in all directions?
Answers
Explanation:
Given polynomial :- 4x²-5x-1
and alpha beta are it's zeros !
• Sum of Zeros =
= \frac{ - coefficient \: of \: x}{coefficient \: of \: {x}^{2} }=
coefficientofx
2
−coefficientofx
\alpha + \beta = \frac{5}{4}α+β=
4
5
• Product of Zeros =
\frac{constant \: term}{coeff. \: \: of \: {x}^{2} }
coeff.ofx
2
constantterm
\alpha \beta = \frac{ - 1}{4}αβ=
4
−1
# To find
{ \alpha }^{2} \beta + \alpha { \beta }^{2}α
2
β+αβ
2
\alpha \beta ( \alpha + \beta )αβ(α+β)
\frac{ - 1}{4} \times \frac{5}{4} = \frac{ - 5}{16}
4
−1
×
4
5
=
16
−5
Answer:
It tells us that the field is perpendicular to the surface, because otherwise it would exert a force parallel to the surface and produce charge motion.
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