why electronic configuration of cr24 is 3d^54s^1 but not 3d^44s^1
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First of all there is a little mistake in the question
The answer is that the 'd' orbital wants to be half filled
Explanation:
The 'd' subshell can hold 10 electrons. If it has 10 electrons then it is full filled and if it has five electrons then it is half filled. Half filled and full filled are the stable states for a shell, every shell wants to stay there. For cr24 it is 3d^54s^1 because the d subshell is half filled and also the 4s subshell. That's why it is 3d^54s^1 and not 3d^4s^2.
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Because one electron from the 4 s orbital is shared to 5d orbital
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