Why H2SO4 is not preferred during the reaxn of alcohol with ki
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In the presence of sulphuric acid (H2SO4), KI produces HI
2KI + H2SO4 → 2KHSO4 + 2HI
Since H2SO4 is an oxidizing agent, it oxidizes HI
2HI + H2SO4 → I2 + SO2 + H2O
As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur.
that's all...hope you understand
2KI + H2SO4 → 2KHSO4 + 2HI
Since H2SO4 is an oxidizing agent, it oxidizes HI
2HI + H2SO4 → I2 + SO2 + H2O
As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur.
that's all...hope you understand
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