Why ia aulphuric acid dowa mot during the teaxtin of alchoks with koh?
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In the presence of H2SO4 KI produces HI
KI + H2SO4 gives HI + KHSO4
Also H2SO4 acts as oxidizing agent
HI + H2SO4 gives I2
Thus reaction of KI with alcohol to produce alkyl iodide cannot occur.
Therefore sulfuric acid is not used during the reaction of KI with Alcohol.
Instead we can use non-oxidizing acid such as H3PO4
KI + H2SO4 gives HI + KHSO4
Also H2SO4 acts as oxidizing agent
HI + H2SO4 gives I2
Thus reaction of KI with alcohol to produce alkyl iodide cannot occur.
Therefore sulfuric acid is not used during the reaction of KI with Alcohol.
Instead we can use non-oxidizing acid such as H3PO4
Answered by
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In the presence of sulphuric acid (H2SO4), KI produces HI
2KI + H2SO4 → 2KHSO4 + 2HI
Since H2SO4 is an oxidizing agent, it oxidizes HI (produced in the reaction to I2).
2HI + H2SO4 → I2 + SO2 + H2O
As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4 is used
hope helps ☺️☺️
2KI + H2SO4 → 2KHSO4 + 2HI
Since H2SO4 is an oxidizing agent, it oxidizes HI (produced in the reaction to I2).
2HI + H2SO4 → I2 + SO2 + H2O
As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4 is used
hope helps ☺️☺️
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