why in a ∆ABC a+b>c,b+c>a,a+c>b ?
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Answer:
Because the SUM OF TWO SIDES OF TRIANGLE IS ALWAYS GREATER THAN THE 3rd Size ....
PROOF -----
Construction: In ΔABC, extend AB to D in such a way that AD=AC.
In ΔDBC, as the angles opposite to equal sides are always equal, so,
∠ADC=∠ACD
Therefore,
∠BCD>∠BDC
As the sides opposite to the greater angle is longer, so,
BD>BC
AB+AD>BC
Since AD=AC, then,
AB+AC>BC
Hence, sum of two sides of a triangle is always greater than the third side.
Hope it helps you ....
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