Question

Why in derivation of 2nd equation of motion using calculus u is taken as constant . however in first and the third equation of motion velocity is not taken as constant and is further integrated​

Answer 1

for second equation of motion

➡️let B=D

➡️let D=B

➡️BD=DC-BC

➡️BD=V-U

➡️a=(V-U)/t

➡️a=BD/t

➡️BD=at

Distance covered by an object -

➡️s=area of rectangle + area of triangle

➡️s=l x b+1/2 x b x h

➡️s=OC+AO+1/2 x BD X AB

➡️s= t x u+1/2 x t x at

➡️s=ut+1/2at²

hope it helps u

Plzzzzzzz follow me

and

mark me as brainliest