why in the reaction of 2-chloro 2-methylpropane with sodium hydroxide there is no formation of 2-methyl-2-propanol.
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23. 2-chloro-2-methylpentane on reaction with sodium methoxide in methanol yields: Strong nucleophile polar solvent (MeOH) gives elimination products Products over substitution products but all products are possible in different yields.
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Answer:
The reaction or 2-chloro 2-methylpropane with does not give 2-methyl 2-propanol because it will undergo elimination reaction .
Explanation :
NaOH will act as strong nucleophile , so instead of undergoing substitution reaction ( addition of -OH) group , it will under go E2 elimination or SN2 reaction. Thereby, eliminating the -Cl and forming 2- methylpropene instead of 2-methyl 2-propanol.
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