why is 3d orbital is filled and not 4s in Zn +2 configuration?
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Explanation:
Zn= 30
Zn2+=30-2=28
E.C.= 1s2 2s2 2p6 3s2 3p6 4s2 3d10
when ionisation is done ...then the outermost shell electrons tend to come out ....thus on applying the required ionisation enthalpy ....the 2 electrons from 4s2( outermost) come out and zn becomes zn2+ and the configuration ends at 3d10
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