Question

Why is a^log base a x=x ?????

Answer 1

↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓

→ Answer :

  $a^{\log_ax}=x$

→ Proof :

Let   $log_ax=b$

By the way logs are defined, we have the relation in this formula.

$=>x=a^b$

Now $b=log_ax$

=> $x=a^{log_ax}$

=> $a^{log_ax}=x$

Hence Proved.

↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑

>>> Hope Helps You <<<