why is cosec 0° undefined? please give the derivation ...
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2
cosec(a) = 1/sin(a)
therefore putting a=0 cosec(0) = 1/sin(0)
but sin(0)=0
therefore, cosec(0)=1/0
hence cosec(0) = undefined
therefore putting a=0 cosec(0) = 1/sin(0)
but sin(0)=0
therefore, cosec(0)=1/0
hence cosec(0) = undefined
Answered by
0
cosec 0 = 1/sin 0
=1/0
=un defined
=1/0
=un defined
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