Why is dot product of two vectors less than product of their modulus?
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By definition, |a×b|= absin∆
And a.b=abcos∆
Where ∆ is the angle between the vectors a and b.
Now, |a×b|=a.b;
=> sin∆=cos∆;
=> tan∆=1;
Which gives a general solution of ∆ as:
∆= nπ+π/4.
But the angle between a and b is simply π/4 or 5π/4.
And a.b=abcos∆
Where ∆ is the angle between the vectors a and b.
Now, |a×b|=a.b;
=> sin∆=cos∆;
=> tan∆=1;
Which gives a general solution of ∆ as:
∆= nπ+π/4.
But the angle between a and b is simply π/4 or 5π/4.
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this is the correct answer
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