Question

Why is freezing point depression of 0.1m sodium chloride is mearly twice that of 0.1 m glucose?

Answer 1

Freezing point is calculated based on vantoff factor.

So, i= (n-1)#+1

• n—)no.of molecules dissociated
• #—)deg.of dissociation (is actually alpha )

So if you take nacl it splits in Na+ and Cl- i.e. two molecules

And if take Glucose(non-electrolyte) has n value eq to 1

(Remember:all non-electrolytes has n value equal to 1 eg. urea,sucrose etc.)

Therefore, freezing point of nacl is 2 times the glucose.

Here I have taken deg of dissociation as 100%

Hope it helped you ❤️